Answer
$ 2e^{x/2}+C$
Work Step by Step
Shortcut: $\displaystyle \int e^{ax+b}dx=\frac{1}{a}e^{a\mathrm{x}+b}+C$
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$a=\displaystyle \frac{1}{2}, b=0, $
$\displaystyle \int e^{x/2}dx==\frac{1}{\frac{1}{2}}e^{\mathrm{x}/2+0}+C$
$=2e^{x/2}+C$