Answer
$ \displaystyle \frac{(2x+4)^{3}}{6}+C$
Work Step by Step
Shortcut formula:
$\qquad $
$\displaystyle \int(ax+b)^{n}dx=\frac{1}{a}\frac{(ax+b)^{n+1}}{n+1}+C \quad($if $n\neq-1)$
$\displaystyle \int(2x+4)^{2}dx=\quad \left[\begin{array}{l}
a=2\\
b=4
\end{array}\right]$
Apply the formula:
$=\displaystyle \frac{1}{2}\cdot\frac{(2x+4)^{2+1}}{2+1}+C$
$= \displaystyle \frac{(2x+4)^{3}}{6}+C$
