Answer
$ -e^{-x}+C$
Work Step by Step
Shortcut: $\displaystyle \int e^{ax+b}dx=\frac{1}{a}e^{a\mathrm{x}+b}+C$
-------------------
$a=-1, b=0, $
$\displaystyle \int e^{-x}dx==\frac{1}{-1}e^{-1\mathrm{x}+0}+C$
$=-e^{-x}+C$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 13 - Section 13.2 - Substitution - Exercises - Page 971: 7
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
