Answer
$ 2e^{0.6x+2}+C$
Work Step by Step
see Substitution RuIe, p.962:
(1)
let $u=0.6x+2$
(2)
$du=0.6dx\displaystyle \ \ \Rightarrow\ \ dx=\frac{du}{0.6}$
$(3)$
$\displaystyle \int 1.2e^{0.6x+2}dx=\int 1.2e^{u}(\frac{du}{0.6})$
... constant multiple, exponential rules
$=\displaystyle \frac{1.2}{0.6}\cdot e^{u}+C$= ... bring back x
$=2e^{0.6x+2}+C$
