Answer
$\int8.1\sqrt {-3x+4}dx=-1.8(-3x+4)^{\frac{3}{2}}+C$
Work Step by Step
Substitution:
$u=-3x+4$
$3x=4-u$
$x=\frac{4}{3}-\frac{1}{3}u$
$dx=-\frac{1}{3}du$
$\int8.1\sqrt {-3x+4}dx=\int8.1\sqrt u(-\frac{1}{3}du)=-2.7\int u^{\frac{1}{2}}du=-2.7(2/3)u^{\frac{3}{2}}+C=-1.8(-3x+4)^{\frac{3}{2}}+C$
