Answer
$3x^{2}y(4x-1)(4x+1)$
Work Step by Step
$ 48x^{4}y-3x^{2}y\qquad$... factor out the common term, $3x^{2}y$
$=3x^{2}y(16x^{2}-1)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$
$=3x^{2}y(4x-1)(4x+1)$
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