Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 91

Answer

$3x^{2}y(4x-1)(4x+1)$

Work Step by Step

$ 48x^{4}y-3x^{2}y\qquad$... factor out the common term, $3x^{2}y$ $=3x^{2}y(16x^{2}-1)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=3x^{2}y(4x-1)(4x+1)$
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