Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 40



Work Step by Step

$ 32y^{2}+4y-6\qquad$...factor out the GCF, $2$. $=2(16y^{2}+2y-3)$ Two factors of $ac=-48$, whose sum is $b=2$ are $8$ and $-6$. Rewrite $2y$ as $8y-6y$ and factor in pairs. $2(16y^{2}+2y-3)$ $=2(16y^{2}+8y-6y-3)\qquad$...factor from each group if possible. $=2[8y(2y+1)-3(2y+1)]\qquad$...factor out the common binomial factor,$2y+1$. $=2(2y+1)(8y-3)$
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