Answer
$2(2y+1)(8y-3)$
Work Step by Step
$ 32y^{2}+4y-6\qquad$...factor out the GCF, $2$.
$=2(16y^{2}+2y-3)$
Two factors of $ac=-48$, whose sum is $b=2$
are $8$ and $-6$.
Rewrite $2y$ as $8y-6y$ and factor in pairs.
$2(16y^{2}+2y-3)$
$=2(16y^{2}+8y-6y-3)\qquad$...factor from each group if possible.
$=2[8y(2y+1)-3(2y+1)]\qquad$...factor out the common binomial factor,$2y+1$.
$=2(2y+1)(8y-3)$
