Answer
$7y^{2}(y+1)^{2}$
Work Step by Step
$ 7y^{4}+14y^{3}+7y^{2}\qquad$...factor out the GCF, $7y^{2}$.
$=7y^{2}(y^{2}+2y+1)\qquad$...recognize a perfect square trinomial.
$(A\pm B)^{2}=A^{2}\pm 2AB+B^{2}$; $A=y,\ B=1$
$=7y^{2}(y+1)^{2}$