Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 25

Answer

$(x+2)(x-3)(x+3)$

Work Step by Step

$ x^{3}+2x^{2}-9x-18\qquad$...group terms with common factors. $=(x^{3}+2x^{2})+(-9x-18)\qquad$...factor from each group. $=x^{2}(x+2)-9(x+2)\qquad$...factor out the common binomial factor,$x+2$. $=(x+2)(x^{2}-9)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(x+2)(x-3)(x+3)$
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