Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 88



Work Step by Step

$ 24a^{4}b+60a^{3}b^{2}+150a^{2}b^{3}\qquad$... factor out the common term, $6a^{2}b$ $=6a^{2}b(4a^{2}+10ab-25b^{2})$
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