Answer
$6a^{2}b(4a^{2}+10ab-25b^{2})$
Work Step by Step
$ 24a^{4}b+60a^{3}b^{2}+150a^{2}b^{3}\qquad$... factor out the common term, $6a^{2}b$
$=6a^{2}b(4a^{2}+10ab-25b^{2})$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 88
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