Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 7

Answer

$(5+x)(x+y)$

Work Step by Step

$ 5x+5y+x^{2}+xy\qquad$...group terms with common factors. $=(5x+x^{2})+(5y+xy)\qquad$...factor from each group. $=x(5+x)+y(5+x)\qquad$...factor out the common binomial factor,$5+x$. $=(5+x)(x+y)$
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