Answer
$5(x-5)(x+2)$
Work Step by Step
$ 5x^{2}-15x-50\qquad$...factor out the GCF, $5$.
$=5(x^{2}-3x-10)$
Two factors of $ac=-10$, whose sum is $b=-3$
are $-5$ and $+2$.
Rewrite $-3x$ as $-5x+2x$ and factor in pairs.
$5(x^{2}-3x-10)$
$=5(x^{2}-5x+2x-10)$
$=5[x(x-5)+2(x-5)]$
$=5(x-5)(x+2)$
