Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 22



Work Step by Step

$ 5x^{2}-15x-50\qquad$...factor out the GCF, $5$. $=5(x^{2}-3x-10)$ Two factors of $ac=-10$, whose sum is $b=-3$ are $-5$ and $+2$. Rewrite $-3x$ as $-5x+2x$ and factor in pairs. $5(x^{2}-3x-10)$ $=5(x^{2}-5x+2x-10)$ $=5[x(x-5)+2(x-5)]$ $=5(x-5)(x+2)$
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