Answer
$(5w-1)(7w+1)$
Work Step by Step
$35w^{2}-2w-1$
Two factors of $ac=-35$, whose sum is $b=-2$
are $-7$ and $5$
Rewrite $-2w$ as$ -7w+5w$ and factor in pairs.
$35w^{2}-2w-1$
$=35w^{2}-7w+5w-1\qquad$...factor from each group if possible.
$=7w(5w-1)+(5w-1)\qquad$...factor out the common binomial factor,$5w-1$.
$=(5w-1)(7w+1)$
