Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 44



Work Step by Step

$35w^{2}-2w-1$ Two factors of $ac=-35$, whose sum is $b=-2$ are $-7$ and $5$ Rewrite $-2w$ as$ -7w+5w$ and factor in pairs. $35w^{2}-2w-1$ $=35w^{2}-7w+5w-1\qquad$...factor from each group if possible. $=7w(5w-1)+(5w-1)\qquad$...factor out the common binomial factor,$5w-1$. $=(5w-1)(7w+1)$
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