Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 16



Work Step by Step

$4x^{2}-x-5=$ Two factors of $ac=-20$, whose sum is $b=-1$ are $4$ and $-5$. Rewrite $x$ as $4x-5x$ and factor in pairs. $4x^{2}-x-5$ $=4x^{2}+4x-5x-5\qquad$...factor from each group. $=4x(x+1)-5(x+1)\qquad$...factor out the common binomial factor,$x+1$. $=(x+1)(4x-5)$
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