Answer
$-6(x-2)(x+1)$
Work Step by Step
$-6x^{2}+6x+12\qquad$...factor out the negative of the GCF, $-6$.
$=-6(x^{2}-x-2)$
Two factors of $ac=-2$, whose sum is $b=-1$
are $-2$ and $1$.
Rewrite $-x$ as $-2x+x$ and factor in pairs.
$-6(x^{2}-x-2)$
$=-6(x^{2}-2x+x-2)\qquad$...factor from each group if possible.
$=-6[x(x-2)+(x-2)]\qquad$
Factor out the common binomial factor,$x-2$.
$=-6(x-2)(x+1)$
