Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 34



Work Step by Step

$-6x^{2}+6x+12\qquad$...factor out the negative of the GCF, $-6$. $=-6(x^{2}-x-2)$ Two factors of $ac=-2$, whose sum is $b=-1$ are $-2$ and $1$. Rewrite $-x$ as $-2x+x$ and factor in pairs. $-6(x^{2}-x-2)$ $=-6(x^{2}-2x+x-2)\qquad$...factor from each group if possible. $=-6[x(x-2)+(x-2)]\qquad$ Factor out the common binomial factor,$x-2$. $=-6(x-2)(x+1)$
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