Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 9



Work Step by Step

$14x^{2}-9x+1=$ Two factors of $ac=14$, whose sum is $b=-9$ are $-7$ and $-2$. Rewrite $-9x$ as $-7x-2x$ and factor in pairs. $14x^{2}-9x+1=14x^{2}-7x-2x+1=$ $=7x(2x-1)-(2x-1)$ $=(2x-1)(7x-1)$
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