Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 21



Work Step by Step

$ 5x^{2}-5x-30\qquad$...factor out the GCF, $5$. $=5(x^{2}-x-6)$ Two factors of $ac=-6$, whose sum is $b=-1$ are $+2$ and $-3$. Rewrite $-x$ as $2x-3x$ and factor in pairs. $5(x^{2}-x-6)$ $=5(x^{2}+2x-3x-6)$ $=5[x(x+2)-3(x+2)]$ $=5(x+2)(x-3)$
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