Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 77

Answer

$x(x+2)(x^{2}-2x+4)$

Work Step by Step

$ x^{4}+8x\qquad$...factor out the common term, $x$ $=x(x^{3}+8)\qquad$...use the sum of two cubes: $\mathrm{A}^{3}+\mathrm{B}^{3} = (\mathrm{A}+\mathrm{B})(\mathrm{A}^{2} - \mathrm{A}\mathrm{B} + B^{2})$ $=x(x^{3}+2^{3})$ $=x(x+2)(x^{2}-2x+4)$
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