Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 39



Work Step by Step

$ 16y^{2}-4y-2\qquad$...factor out the GCF, $2$. $=2(8y^{2}-2y-1)$ Two factors of $ac=-8$, whose sum is $b=-2$ are $-4$ and $2$. Rewrite $-2y$ as $-4y+2y$ and factor in pairs. $2(8y^{2}-2y-1)$ $=2(8y^{2}-4y+2y-1)\qquad$...factor from each group if possible. $=2[4y(2y-1)+(2y-1)]\qquad$...factor out the common binomial factor,$2y-1$. $=2(2y-1)(4y+1)$
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