Answer
$(2y+1)(10y+1)$
Work Step by Step
$20y^{2}+12y+1$
Two factors of $ac=20$, whose sum is $b=12$
are $10$ and $2$.
Rewrite $12y$ as $10y+2y$ and factor in pairs.
$20y^{2}+12y+1$
$=20y^{2}+10y+2y+1\qquad$...factor from each group if possible.
$=10y(2y+1)+(2y+1)\qquad$...factor out the common binomial factor,$2y+1$.
$=(2y+1)(10y+1)$
