Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 50



Work Step by Step

$20y^{2}+12y+1$ Two factors of $ac=20$, whose sum is $b=12$ are $10$ and $2$. Rewrite $12y$ as $10y+2y$ and factor in pairs. $20y^{2}+12y+1$ $=20y^{2}+10y+2y+1\qquad$...factor from each group if possible. $=10y(2y+1)+(2y+1)\qquad$...factor out the common binomial factor,$2y+1$. $=(2y+1)(10y+1)$
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