Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 10



Work Step by Step

$3x^{2}+2x-5=$ Two factors of $ac=-15$, whose sum is $b=+2$ are $+5$ and $-3$. Rewrite $2x$ as $5x-3x$ and factor in pairs. $3x^{2}+2x-5=3x^{2}+5x-3x-5=$ $=x(3x+5)-(3x+5)$ $=(3x+5)(x-1)$
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