Answer
$(3xy+2)(9x^{2}y^{2}-6xy+4)$
Work Step by Step
$ 27x^{3}y^{3}+8\qquad$...use the sum of two cubes: $\mathrm{A}^{3}+\mathrm{B}^{3} = (\mathrm{A}+\mathrm{B})(\mathrm{A}^{2} - \mathrm{A}\mathrm{B} + B^{2})$
$=(3xy)^{3}+2^{3}$
$=(3xy+2)((3xy)^{2}-3xy\cdot 2+2^{2})$
$=(3xy+2)(9x^{2}y^{2}-6xy+4)$
