Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 86

Answer

$(x+2y)(x-6y)$

Work Step by Step

$x^{2}-4xy-12y^{2}$ ... Searching for two factors of $ac=-12$ whose sum is $b=-4,$ we find$\qquad 2$ and $-6.$ Rewrite the middle term and factor in pairs: $=x^{2}+2xy-6xy-12y^{2}=$ $=x(x+2y)-6y(x+2y)$ = $(x+2y)(x-6y)$
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