Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 43



Work Step by Step

$4w^{2}+8w-5$ Two factors of $ac=-20$, whose sum is $b=8$ are $10$ and $-2$. Rewrite $8w$ as$ 10w-2w$ and factor in pairs. $4w^{2}+8w-5$ $=4w^{2}+10w-2w-5\qquad$...factor from each group if possible. $=2w(2w+5)-(2w+5)\qquad$...factor out the common binomial factor,$2w+5$. $=(2w+5)(2w-1)$
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