Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 80



Work Step by Step

$ 2y^{5}-128y^{2}\qquad$...factor out the common term, $2y^{2}$ $=2y^{2}(y^{3}-64)\qquad$...use the difference of two cubes: $\mathrm{A}^{3}-\mathrm{B}^{3} = (\mathrm{A}-\mathrm{B})(\mathrm{A}^{2} + \mathrm{A}\mathrm{B} + B^{2})$ $=2y^{2}(y^{3}-4^{3})$ $=2y^{2}(y-4)(y^{2}+4y+16)$
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