## Introductory Algebra for College Students (7th Edition)

$(y+2)^{2}(y-2)$
$y^{3}+2y^{2}-4y-8\qquad$...factor in groups. $=(y^{3}+2y^{2})+(-4y-8)$ $=y^{2}(y+2)-4(y+2)\qquad$...factor out the common binomial factor,$y+2$. $=(y+2)(y^{2}-4)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(y+2)(y-2)(y+2)$ $=(y+2)^{2}(y-2)$