Answer
$3a^{2}(4a-1)(4a+1)$
Work Step by Step
$ 48a^{4}-3a^{2}\qquad$...factor out the common term, $3a^{2}$
$=3a^{2}(16a^{2}-1)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$
$=3a^{2}(4a-1)(4a+1)$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 60
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