Answer
$(7+x)(x+y)$
Work Step by Step
$ 7x+7y+x^{2}+xy\qquad$...group terms with common factors.
$=(7x+x^{2})+(7y+xy)\qquad$...factor from each group.
$=x(7+x)+y(7+x)\qquad$...factor out the common binomial factor,$7+x$.
$=(7+x)(x+y)$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 8
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