Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 87

Answer

$12a^{2}(6ab^{2}+1-2a^{2}b^{2})$

Work Step by Step

$ 72a^{3}b^{2}+12a^{2}-24a^{4}b^{2}\qquad$... factor out the common term, $12a^{2}$ $=12a^{2}(6ab^{2}+1-2a^{2}b^{2})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.