Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 87



Work Step by Step

$ 72a^{3}b^{2}+12a^{2}-24a^{4}b^{2}\qquad$... factor out the common term, $12a^{2}$ $=12a^{2}(6ab^{2}+1-2a^{2}b^{2})$
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