Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 4

Answer

$(10x-9)(10x+9)$

Work Step by Step

$ 100x^{2}-81\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(10x)^{2}-9^{2}$ $=(10x-9)(10x+9)$
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