Answer
$(6xy+5)(36x^{2}y^{2}+30xy+25)$
Work Step by Step
$ 216x^{3}y^{3}+125\qquad$...use the sum of two cubes: $\mathrm{A}^{3}+\mathrm{B}^{3} = (\mathrm{A}+\mathrm{B})(\mathrm{A}^{2} - \mathrm{A}\mathrm{B} + B^{2})$
$=(6xy)^{3}+5^{3}$
$=(6xy+5)((6xy)^{2}-6xy\cdot 5+5^{2})$
$=(6xy+5)(36x^{2}y^{2}-30xy+25)$
