Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 15



Work Step by Step

$6x^{2}+x-15$ Two factors of $ac=-90$, whose sum is $b=1$ are $10$ and $-9$. Rewrite $x$ as $10x-9x$ and factor in pairs. $6x^{2}+x-15$ $=6x^{2}+10x-9x-15\qquad$...factor from each group. $=2x(3x+5)-3(3x+5)\qquad$...factor out the common binomial factor,$3x+5$. $=(3x+5)(2x-3)$
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