Answer
$(3x+5)(2x-3)$
Work Step by Step
$6x^{2}+x-15$
Two factors of $ac=-90$, whose sum is $b=1$
are $10$ and $-9$.
Rewrite $x$ as $10x-9x$ and factor in pairs.
$6x^{2}+x-15$
$=6x^{2}+10x-9x-15\qquad$...factor from each group.
$=2x(3x+5)-3(3x+5)\qquad$...factor out the common binomial factor,$3x+5$.
$=(3x+5)(2x-3)$
