Answer
$2x^{2}(x+4)(x^{2}-4x+16)$
Work Step by Step
$ 2x^{5}+128x^{2}\qquad$...factor out the GCF, $2x^{2}$.
$=2x^{2}(x^{3}+64)\qquad$...use the sum of two cubes: $\mathrm{A}^{3}+\mathrm{B}^{3} = (\mathrm{A}+\mathrm{B})(\mathrm{A}^{2} - \mathrm{A}\mathrm{B} + B^{2})$
$=2x^{2}(x+4^{3})$
$=2x^{2}(x+4)(x^{2}-4x+16)$
