Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 69



Work Step by Step

$ 2y^{3}+3y^{2}-50y-75\qquad$...factor in groups. $=(2y^{3}+3y^{2})+(-50y-75)$ $=y^{2}(2y+3)-25(2y+3)\qquad$...factor out the common binomial factor,$2y+3$. $=(2y+3)(y^{2}-25)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(2y+3)(y-5)(y+5)$
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