Answer
$(2y+3)(y-5)(y+5)$
Work Step by Step
$ 2y^{3}+3y^{2}-50y-75\qquad$...factor in groups.
$=(2y^{3}+3y^{2})+(-50y-75)$
$=y^{2}(2y+3)-25(2y+3)\qquad$...factor out the common binomial factor,$2y+3$.
$=(2y+3)(y^{2}-25)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$
$=(2y+3)(y-5)(y+5)$
