Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 74

Answer

$y^{5}(y^{2}+1)(y-1)(y+1)$

Work Step by Step

$ y^{9}-y^{5}\qquad$...factor out the common term, $y^{5}$ $=y^{5}(y^{4}-1)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=y^{5}(y^{2}-1)(y^{2}+1)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=y^{5}(y^{2}+1)(y-1)(y+1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.