Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 26

Answer

$(x+3)(x-5)(x+5)$

Work Step by Step

$ x^{3}+3x^{2}-25x-75\qquad$...group terms with common factors. $=(x^{3}+3x^{2})+(-25x-75)\qquad$...factor from each group. $=x^{2}(x+3)-25(x+3)\qquad$...factor out the common binomial factor,$x+3$. $=(x+3)(x^{2}-25)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(x+3)(x-5)(x+5)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.