Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 64



Work Step by Step

$21x^{2}-25x-4$ Two factors of $ac=-84$, whose sum is $b=-25$ are $3$ and $-28$. Rewrite the middle term and factor in pairs. $21x^{2}-25x-4$ $=21x^{2}+3x-28x-4$ $=3x(7x+1)-4(7x+1)]\qquad$...factor out the common binomial factor,$7x+1$. $=(7x+1)(3x-4)$
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