Answer
$-2(y+7)(y-8)$
Work Step by Step
$-2y^{2}+2y+112\qquad$...factor out the negative of the GCF, $-2$.
$=-2(y^{2}-y-56)$
Two factors of $ac=-56$, whose sum is $b=-1$
are $7$ and $-8$.
Rewrite $-y$ as $7y-8y$ and factor in pairs.
$-2(y^{2}-y-56)$
$=-2(y^{2}+7y-8y-56)\qquad$...factor from each group.
$=-2[y(y+7)-8(y+7)]\qquad$...factor out the common binomial factor,$y+7$.
$=-2(y+7)(y-8)$
