Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 33



Work Step by Step

$-2y^{2}+2y+112\qquad$...factor out the negative of the GCF, $-2$. $=-2(y^{2}-y-56)$ Two factors of $ac=-56$, whose sum is $b=-1$ are $7$ and $-8$. Rewrite $-y$ as $7y-8y$ and factor in pairs. $-2(y^{2}-y-56)$ $=-2(y^{2}+7y-8y-56)\qquad$...factor from each group. $=-2[y(y+7)-8(y+7)]\qquad$...factor out the common binomial factor,$y+7$. $=-2(y+7)(y-8)$
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