Answer
$(4y-1)(3y-2)$
Work Step by Step
$12y^{2}-11y+2$
Two factors of $ac=24$, whose sum is $b=-11$
are $-3$ and $-8$.
Rewrite the middle term and factor in pairs.
$12y^{2}-11y+2$
$=12y^{2}-3y-8y+2$
$=3y(4y-1)-2(4y-1)]\qquad$...factor out the common binomial factor,$4y-1$.
$=(4y-1)(3y-2)$
