Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 63



Work Step by Step

$12y^{2}-11y+2$ Two factors of $ac=24$, whose sum is $b=-11$ are $-3$ and $-8$. Rewrite the middle term and factor in pairs. $12y^{2}-11y+2$ $=12y^{2}-3y-8y+2$ $=3y(4y-1)-2(4y-1)]\qquad$...factor out the common binomial factor,$4y-1$. $=(4y-1)(3y-2)$
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