Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 462: 55



Work Step by Step

$-4y^{3}+28y^{2}-40y\qquad$...factor out the common term, $-4y$ $=-4y(y^{2}-7y+10)$ Two factors of $ac=10$, whose sum is $b=-7$ are $-5$ and $-2$. Rewrite the middle term and factor in pairs. $-4y(y^{2}-7y+10)$ $=-4y(y^{2}-2y-5y+10)$ $=-4y[y(y-2)-5(y-2)]\qquad$...factor out the common binomial factor,$y-2$. $=-4y(y-2)(y-5)$
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