Answer
The integral is not improper.
Work Step by Step
The bounds of the integral are not $\pm\infty$. In addition, the integrand $e^{-x}$ does not pass through any vertical asymptotes on $[0,2]$. Therefore, the integral is not improper.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.8 Exercises - Page 575: 5
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