Answer
It is not improper.
Work Step by Step
Neither of the bounds are $\pm\infty$, and the function has no vertical asymptotes on $[1,2]$. Therefore, the integral is not improper.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.8 Exercises - Page 575: 2
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