Answer
Converges
$\frac{1}{2}$
Work Step by Step
$\int ^{\infty }_{1}\dfrac {1}{x^{3}}dx=-\dfrac {1}{2x^{2}}]^{\infty }_{1}=0-\left( -\dfrac {1}{2}\right) =\dfrac {1}{2}$
So the integral converges
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.8 Exercises - Page 575: 17
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