Answer
The integral is not improper.
Work Step by Step
The bounds of the integral are not $\pm\infty$. The denominator of the integrand can be factored into $x^2-5x+6=(x-2)(x-3)$. However, over the domain $[0,1]$, the denominator is not zero, and the integrand does not pass any vertical asymptotes. Therefore, the integral is not improper.
