Answer
$\int^{1}_{0}\frac{dx}{5x-3}$ is improper
Work Step by Step
First, it is important to understand what an improper integral is. An improper integral is an integral that has a limit of integration as $\infty$ or the function has a finite number of discontinuities over its interval.
$\int^{1}_{0}\frac{dx}{5x-3}$ is improper because $5x-3 = 0$ and because $5x-3 = 0$, then $x=\frac{3}{5}$.
Because $0 \leq \frac{3}{5} \leq 1$, the integral is improper.
