Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 14 - Multiple Integration - 14.1 Exercises - Page 972: 5

Answer

$\frac{4x^2-x^4}{2}$

Work Step by Step

$\int ^{\sqrt {4-x^2}} _0 x^2ydy$ $[1/2(x^2)(y^2)]^{\sqrt {4-x^2}} _0$ $\frac{4x^2-x^4}{2}$
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