Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 14 - Multiple Integration - 14.1 Exercises - Page 972: 18

Answer

$ =e^{-1}-4e^{-4}\approx 0.295$

Work Step by Step

$\int ^{4}_{1}\int ^{\sqrt {x}}_{1}2ye^{-x}dydx=\int ^{4}_{1}2\times \dfrac {1}{2}y^{2}]^{\sqrt {x}}_{1}e^{-x}dx=\int ^{4}_{1}\left( x-1\right) e^{-x}dx=-xe^{-x}]^{4}_{1}=-4e^{-4}-\left( -1\times e^{-1}\right) =e^{-1}-4e^{-4}\approx 0.295 $
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