Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 90



Work Step by Step

Given: $9(x-4)+y^2(4-x)$ This implies that $=9(x-4)-y^2(x-4)$ or, $=(9-y^2)(x-4)$ or,$=(3-y)(3+y)(x-4)$ Hence, our Factors are: $(3-y),(3+y),(x-4)$
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