Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 16



Work Step by Step

Given:$(6x^3)(\dfrac{1}{3}x^5-4x^2-2)$ Multiply the given polynomials. This implies $(6x^3)(\dfrac{1}{3}x^5-4x^2-2)=2x^{3+5}-24x^{3+2}-12x^3$ Hence, the result is : $=2x^8-24x^5-12x^3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.