## Intermediate Algebra for College Students (7th Edition)

$2x^8-24x^5-12x^3$
Given:$(6x^3)(\dfrac{1}{3}x^5-4x^2-2)$ Multiply the given polynomials. This implies $(6x^3)(\dfrac{1}{3}x^5-4x^2-2)=2x^{3+5}-24x^{3+2}-12x^3$ Hence, the result is : $=2x^8-24x^5-12x^3$