Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 88

Answer

$(y-5),(y+5),(y+2)$

Work Step by Step

Given: $y^3+2y^2-25y-50$ This implies that $=y^2(y+2)-25(y+2)$ or, $=(y^2-25)(y+2)$ or,$=(y-5)(y+5)(y+2)$ Hence, our Factors are: $(y-5),(y+5),(y+2)$$
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